Among the given pairs,in which pair does the | vedclass

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(C) The enol content is determined by the stability of the resulting enol form. Aromaticity is a major factor in stabilizing the enol form.In option $

Vedclass · Accepted Answer

Cyclopent$-2-$en$-1-$one anion and cyclopent$-2-$en$-1-$one

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(C) The enol content is determined by the stability of the resulting enol form. Aromaticity is a major factor in stabilizing the enol form.In option $(C)$,the first compound is the cyclopentadienyl anion derivative (cyclopent$-2-$en$-1-$one anion). Its enol form is the cyclopentadienyl anion,which is aromatic ($6 \pi$ electrons) and thus highly stable.The second compound is cyclopent$-2-$en$-1-$one,whose enol form is phenol (if it were a cyclohexadienone derivative) or a simple enol,which is significantly less stable than the aromatic anion formed from the first compound.Therefore,the second compound has less enol content than the first compound.

Among the given pairs,in which pair does the second compound have less enol content than the first compound?

Similar Questions

Consider the following compound $(X)$:
$H-C \equiv C-CH_2-CH(CH_3)-CH_3$
The most stable and least stable carbon radicals,respectively,produced by homolytic cleavage of the corresponding $C-H$ bond are:

Which one of the following is most stable?

Which among the following carbocations is the most reactive?

Which of the following is more stable than the remaining three?

Which of the following intermediates is more stable?

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